Linear wave or photon wave

Enviado por Geraldo em qua, 01/23/2008 - 02:27.

 

 

 

Photons emitted at the same time by a light fount create surface of concentric sphere that increase with velocity c. Those photons sphere works apparently as a spheric luminous waves, which the rays that are created by photons are the own waves.
So, a light ray is a linear wave.

The time break Dt of emission, in the time unit, of each photon in the same polarization by fount A determines this linear wave’s frequency f.
– The distance between photons of the same polarization determines the wave’s length l of the linear wave that does not have amplitude.
– The velocity of photon’s emission is always c, where c = l f, being:
f = quantity of photons of the same polarization emitted in a determined time unit;
l = set distance between each photon of the same polarization;
f = 5,976096 x 1014 Hz;
l = 5,02 x 10-7 m.

All the light’s sources on the universe emit photons always on the same way with a determined wave’s length l = 5,02 x 10-7 m, a determined frequency f = 5,976096 x 1014 Hz and constant velocity c = 299.792.458 m/s.

Linear wave propagation in a vacuum

As photon is a particle, it is not necessary to have a material support (ether) to propagate, working at top speed.

Arrival’s velocity of the linear wave on the receiver

 

We verified that photons are influenced by source’s velocity according to an observer’s viewpoint. Thus, on the earth, knowing about the deviation velocity Va of a galaxy, their photons will reach us with a velocity c1, where c1 = c – Va.
When we measure the frequency f´ of the light’s arrival from a galaxy, the arrival velocity c1 of the photons can be calculated by the formula of the undulatory physic v = l f.
Thus, we have c1 = lf´, where:
c1 = velocity of photons´ arrival;
f´= frequency of these photons´ arrival.
Example: If the light of a galaxy arrives with a frequency f ´= 4,498304 x 1013 Hz, we can have c1, as it follows:
c1 = 4,498304 x 1013 x 5,0909 x 10-7 = 22,9004158336 x 106 m/s, ou então, c1 = 0,076334712 c.

Doppler effect on the linear wave

This effect provides an arrival’s frequency f´ of a wave when we know:

– The deviation’s velocity Va of the source;
- The emission’s velocity of this source;
- Its emission’s frequency f;
We can use the Doppler effect’s formula on the linear wave.
As it is shown:

The galaxy CLASXS 509 that, according to astronomic catalogue has redshift Z = 1,016.
This value Z provides us a deviation velocity Va, by the formula , thus:
Va = 0,605075257 c.

Thus:

f = 5,02 x 1014 Hz (frequency of wave’s emission),
c = 1 (velocity unit),
We will obtain from the Doppler effect formula:
f´= 5,976096 x 1014 x (1 - 0,605075257),
f´= 2,360108 x 1014 Hz,
That is the arrival’s frequency of the linear wave of light on the receiver.