Dynamic of real universe

Spreadsheet of real universe

Based on Newton’s concepts, which says that photon is influenced by the speed of its source, which is in accord with “Logical Deductions” when it reports that the observer in the absolute space sees the complete functioning of light and he sees the real motions in the universe as well. Thus, we have developed a mathematic spreadsheet, in which we can simulate the dynamic of any two galaxies and the motion of photons and light ray between them as well. We will use in such spreadsheet a simple mathematic. You just need to know how to calculate the six components of triangle; it means, the tree sides and tree angles when 3 of such 6 data provided are
For simulating the dynamic between two galaxies, at first we need to define their positions in the universe:
Thus, let’s consider a galaxy P and a galaxy L. Let’s consider galaxy L as Milky Way (Earth). As we already know the age of Earth T, we just need to know their expansion speed Vp and Vt and the angle Ô that both have made when they were created – Big Bang, for situating them in the universe
Science already knows:
- speed of light: c = 300.000 Km/s;
- Earth’s age T = 13.7 billion years.
Logical Deductions determines:
- frequency of light´s emission f = 5.8928 x 1014 Hz;
- the wave’s length on emission of light = 5,0909 x 10-7m.
At first, in accord with data of both galaxies that will be simulated and also with the center of universe O, we will find the triangle OPL on the plane provided by direction of both galaxies, where we have:
- P = actual position of galaxy P;
- L = actual position of galaxy L (Earth);
- O = center of universe, where Big Bang took place.
Considering positions P1 and L1 of galaxies P and L, when the photon that arrives at L (Earth) nowadays was emitted; thus, besides triangle OPL we will also have triangles OP1L1, OL1P1, P1L1L, and P1LP.

Developing such 5 triangles we have obtained all sides in the simulation of dynamic between galaxies P and L (Earth) and also photon between them.
For solving such triangles, we have created the spreadsheet below that can be calculated by computer.

Elaboration of spreadsheet of real universe.

Spreadsheet’s creation
We already know::

[1] The light´s speed in vacuum:
c = 300.000 Km/s ( or any unit of speed = 1);

[2] The actual universe’s age provided by NASA in 2003:
T = 13,7 billion years

[3] The frequency of light´s emission::
f = 5,8928 x 1014 Hz;

[4] The wave’s length on light´s emission:
l = 5,0909 x 10-7 m.

We use the following variables:

[5] The Earth’s expansion speed:

Vt.

[6] The expansion speed of galaxy P:
Vp.

[7] The angle formed between expansion directions of Earth and galaxy P in triangle OLP:

Ang Ô.

We calculate:

[8] The actual distance A between the center of universe O and Earth L:

A = Vt x T

[9] The actual distance B between the center of universe O and galaxy P:

B = Vp x T

[10] We already know the actual distance D between Earth L and galaxy P, thus we can solve the triangle OLP:

[11] The time T2 that a photon takes to arrive at Earth seen by an observer on reference of galaxy P:

- We must remember that the photon’s speed is always c for an observer on the reference of the source, and in a T2:

the Earth goes from position L1 toward L at speed Vt;

the galaxy P goes from P1 toward P at speed Vp:

the photon goes from P1 toward L, covering the distance D2 at speed c2, seen by an observer S in the absolute space:

the photon covers the distance D, going from P toward L, at speed c, seen by an observer on P;

the photon covers distance D1 at speed c1, going from P1 toward L1, seen by an observer on the reference frame of Earth.

[12] The universe´s age when the photon was emitted.

T1 = T - T2;

[13] The angle M formed between the direction OP of expansion of galaxy P and its deviation direction LP in triangle OLP:

[14] The angle B formed between the direction OL of Earth’s expansion and the direction LP of deviation of galaxy P in the triangle OPL:

[15] The sum 1 of internal angles of triangle OLP (to verify the consistence of calculus):

In the triangle OLP:

[16] The distance b from O toward P1:

b = Vp x T1

[17] The distance b1 from P1 toward P:

b1 = Vp x T2

[18] The real trajectory D2 covered by photon from P1 toward L seen by observer S in the absolute space is obtained when we solve the triangle OP1L:

[19] The angle  formed between the direction OL of Earth’s expansion and the real trajectory of photon P1L, in the triangle OLP1:

[20] The angle L formed between the direction OP1 of expansion of galaxy P and the trajectory of photon P1L, is obtained when we solve the triangle OLP1:

[21] The sum 2 of internal angles of the triangle A OLP1 (to verify the consistence of calculus):

 

[22] The distance "a" from Earth on L1 toward the universe’s center O:

[23] The distance a1 covered by Earth from position L1 toward L:

[24] The distance D1 between P1 and L1 in the triangle OLP1:

[25] The speed of photon c2 in its real trajectory D2:

[26] The speed of approach of photon c1 to Earth between P1 and L1 for an observer on Earth:

[27] The supplement of âng.B:

[28] The angle of change on direction of photon in its emission due to the expansion speed Vp of galaxy P.

[29] The deviation speed V1 between P and L due to the speed Vp, which is the projection of Vp under axle LP.

[30] The deviation speed V2 between P and L due to speed Vt that is the projection of Vt under axle LP:

[31] The deviation speed Va between galaxy P and Earth, for an observer on Earth that thinks he is standing still:

[32] The add 3 of internal angles of triangle P1L1L (to verify the consistence of calculus):

 

[33] The speed of a fictitious photon c4 for the observer S located in the absolute space, between galaxy P and Earth:

(the positive sign occurs due to the value of cos L, which is negative, where we must use the supplement of angle L);

For the observer S the real trajectory of photon is P1L, at speed c2. However, if a fictitious photon went from P toward L at speed c4, in a time T2, we could solve the triangle PP1L and also find out the value of c4 that will always be c4 = 1; Meanwhile, for an observer on galaxy P, this is the real trajectory of photon at speed c = 1. This is another prove about the consistence of our spreadsheet, because for any galaxy P the calculus of c4 is always c4 = 1.

[34] The angle of aberration E of photon upon arriving at Earth:

* Look at such interesting result [28] âng E1 = [34] âng E. It means that the angle of change on direction of photon in its emission from c to c2, is the same as changes on photon in its arrival at Earth when c2 turns into c1, for any galaxy P, regardless of value of its speed Vp.

[35] Another way to calculate c1, considering changes from c2 to c1 due to the speed Vt of expansion of Earth (L) and to the aberration effect:

[36] Another way to calculate speed c, considering the observer on Earth ( in his truth, the galaxy P deviates at speed Va and the photon emitted from P1 at speed c):

*Look at the values [26] c1 = [35] c1a = [36] c1b. It is an evidence of the internal consistence of our spreadsheet.

[37] The definition of constant of Hubble H0 is the deviation speed Va of galaxy P divided by its distance D toward Earth covered by the photon at speed c seen by observer P:

[38] add 4 of internal angles of triangle PP1L ( to verify the consistence of calculus):

 

[39] The redshift Z of galaxy P defined by Science through the formula below:

[40] The frequency pf light f’ upon arriving at Earth, calculated by formula of Doppler Effect:

[41] Another way to calculate f’, through the formula v = l x f of wave’s speed:

where v = c1,
Being:
c1= real speed of arrival of photon;
f ' = frequency of arrival of light.

Look at the values [40] f´ = [41] f´1, which are another evidence of the consistence of our spreadsheet.

[42] The maximum value of âng. O, so that galaxy P is in the visible universe of Earth.

 

PS: In this example, the angle O’ was not calculated, because Vt<c.

For you testing the functioning of such spreadsheet, please download it by pressing here.